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Basic Solar Math

How much electricity is produced by a solar panel? What about a roof-top installation?
You will find some basic calculations here below.

The Watt measures the rate of energy conversion and it is the main unit of power used in photovoltaics.

1 kilowatt (kW) 1000 watts
1 megawatt (MW) 1000 kW or 1000000 watts
1 gigawatt (GW) 1000 MW or 1000000000 watts
1 Terrawatt (TW) 1000 GW or 1000000000000 watts
Wp P = peak (peak-performance of a module)

 

How much energy does one panel produces?

Electrical energy is generally measured in kilowatt-hours (kWh). If a solar panel produces 100 watts for 1 hour, it has produced 100 watt-hours or 0.1 kWh.

The amount of energy produced per day will depend on the area, shading, orientation, and watt-class of the panel.

In areas with high irradiation, a properly oriented panel that produces 100 Watts at noon on a sunny day will produce an average of about 0.5 kWh/day during the winter and 0.8 kWh/day during the summer months.

In an area with low irradiation, the same panel will still produce about 0.25 kWh/day during the winter and 0.6 kWh/day during summer months.

An effective orientation for a solar panel  installation is 100 percent south, at an angle of 10-20°.

There are several standard measurements to describe a solar panel installation. 

NOMINAL SYSTEM SIZE 

number of panels x watt class per panel

Ex: Pig Farm in Gadendorf, Germany

434 panels x 215 REC AE-series panels = 93.31 kW system

 

ANNUAL CAPACITY

number of sun hours for the region x system size (also called "effect") x performance ratio (80-85%)

Following the same example as in the calculation below:

1 380 sun hours x 93.31 system size x 80 % = 103 014 kWh

It is also possible to use a solar radiation map to determine the sun hours.
Furthermore it is often advisable to insert a correction factor of 1.1 (an average value representing roof-top angle, orientation, shadowing etc.).

 

ANNUALLY SAVED AMOUNT OF CO2

CO2- reduction in electricity- local mix (Germany 650 kg pr 1000 kWh) x annual capacity

For this example:

0.65 kg/ kWh x 78,791 kWh =  51.214 tons annual CO2 savings.
 

HOUSEHOLD EQUIVALENT POWER PRODUCTION PER YEAR

annual capacity / average electricity consumption

To determine how much electricity per household is produced by this farm, we need to know the average electricity consumption for a family of four, in Germany is it 4.500 kWh. So:

78 791 kWh / 4 500 kWh = 17.5 

This number means that this installation produces enough electricity to satisfy the needs of 17.5 families per year.